@Ravindra: Can you explain the algorithm for step 3 in more detail? I
don't yet see how you do it in O(n^2), since it seems to me that
comparing one A[i,j] to all the A[j,k] is already O(n^2). What am I
missing?

Dave

On Oct 24, 12:05 am, ravindra patel <[email protected]> wrote:
> Can be done in O(n^2) time using the slope as people suggested above.
>
> 1- Sort the points in increasing order of x cord. O(nlogn)
> 2- prepare a n*n matrix A where A[i,j] = slope( point(i), point(j) )  -
> O(n^2) [Note that point i and j are sorted in increasing order of x]
> 3- find a pair of A[i,j] and A[j,k] with same slope. [Can be done in O(n^2)]
>
> Thanks,
> - Ravindra
>
>
>
> On Sun, Oct 24, 2010 at 10:11 AM, Dave <[email protected]> wrote:
> > @Preetika: Then you have to look for duplicates in an array of n(n-1)/
> > 2 real numbers. I think this takes the complexity above O(n^2).
>
> > Dave
>
> > On Oct 23, 10:54 pm, preetika tyagi <[email protected]> wrote:
> > > You have to scan every pair of points only once to get the value of 'm'
> > and
> > > 'a', so the time complexity would be O(n^2).
>
> > > On Sat, Oct 23, 2010 at 6:22 PM, Meng Yan <[email protected]>
> > wrote:
> > > > there are (n*(n-1))/2pairs of points. I think if we use your method,
> > the
> > > > time complexity should be O(n^4).
>
> > > > Is it possible to put all points into k different domain and using
> > > > T(n)=T(n/k)+f(n) to solve this problem?
>
> > > > On Sat, Oct 23, 2010 at 7:51 PM, preetika tyagi <
> > [email protected]>wrote:
>
> > > >> Is there any specific need to use recursion?
>
> > > >> One alternate is to find slope and constant (m and c) for every pair
> > of
> > > >> points and same value of m & c will specify the points on the same
> > line.
> > > >> Time complexity is O(n*n).
>
> > > >> On Sat, Oct 23, 2010 at 4:31 PM, Meng Yan <[email protected]
> > >wrote:
>
> > > >>> Given n point on the plane, find out whether any 3point on the same
> > > >>> line.
>
> > > >>> How to use recursion to solve the problem? Could you help me find the
> > > >>> algorithm and give the time complexity?
>
> > > >>> Bests,
> > > >>> Claire
>
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