If the first element A1 is less than or equal to the last one Am, then n = 0; else (A1>Am), use divide-and-conquer to find element A[i], A[i]<=Am while A[i-1] >= A1.

On 2010-10-29 7:49, preetika tyagi wrote:
/A “rotated array” is an array of integers in ascending order, after which for every element i, it has been moved to element (i + n) mod sizeOfList. Write a function that takes a rotated array and, in less-than-linear time, returns n (the amount of rotation).

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