@jai
yeah, it can be done using count sort logic
but that will take O(n) extra space

which can be avoided by using XOR.

On Fri, Dec 10, 2010 at 3:34 AM, jai gupta <[email protected]> wrote:

> Algo:
> In first traverse find the min and the max values.
> if (max-min)  not equals (N-1)
> return false
> In next traverse map each in a hashtable of size N where index=key-min. Now
> in case of collision return false
> return true
>
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-- 
Regards
Aditya Kumar
B-tech 3rd year
Computer Science & Engg.
MNNIT, Allahabad.

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