ya all the exprn is evaluated and left expr is assigned .. On Dec 13, 9:21 pm, siva viknesh <[email protected]> wrote: > #include<stdio.h> > int main() > { > int a=1,b=2,c=3; > > c=--a,b++ - c; > > printf("%d %d %d",a,b,c); > return 0; > > } > > the above code is perfectly valid and prints "0 3 0" ... > > but how "comma" is evaluated and the value assigned to variable 'c' is the > expression evaluated on the RHS of comma....is there any such rules in C ??
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