Hi,
Very good question.

i think very knows brute-force soln of n^3 time complexity.

here is a alternative method/soln of O(n^2 * log(n)) time complexity Algo

1) pick any number from list A (One by one)...... let say 'x'

2) pick any number from list B (one by one )...... let say 'y'

3) z=x+y

4)look for 'z' in the list by considering all numbers as unsigned if u found
then check sign of that number it be opposite of 'z' if so return 1 else 0

[above steps is repeated for all elements]

*correct me if I am wrong*

-- 
Prashant Kulkarni
IISc Bangalore




On Wed, Dec 15, 2010 at 10:36 AM, Soumya Prasad Ukil
<[email protected]>wrote:

> Are the linked list sorted?
>
>
> On 14 December 2010 05:33, divya <[email protected]> wrote:
>
>> Given three lists: A, B and C of length n each. Write a function which
>> returns true if any 3 three numbers (1 from each list), sum up to
>> zero. Else return false, if there is no such combination.
>>
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> regards,
> soumya prasad ukil
>
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