main()
> {
>> int a[5]={1,3,6,7,0};
>> int *b;
>> b=&a[2];
>> cout<<b[-1];
>> }
>>
>> the value of b[-1] is
>> a.1
>> b.3
>> c.-6
>> d.none
>>
>>
ANS will be 3.
Because Compiler internally first converted in the form as *(b-1) , and get
the one position back at the position 3.
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