If we rewrite question in terms of Probability, call to foo2() depends on
two events:
1. (E1) A > B, probablity 75%.
2. (E2) C < D, again probability 75%.
Probability (E) = Prob(E1) * Prob(E2) = 75/100 * 75/100 * 5000 = 2812.50
times.
Correct me if wrong.
- Dinesh Bansal
On Wed, Dec 15, 2010 at 12:36 AM, bittu <shashank7andr...@gmail.com> wrote:
>
> void foo1()
> {
> if(A<B)
> Then {_/*.... */}
> else
> if(C<D)
> then foo2()
> }
>
> How many time foo2() would get called given
> A<B 25% of the times and C<D 75% of the times and foo1() is called
> 5000 times
>
> although i had diff...solution..but i wants to confirm wid others..so
> hav a look
>
> Regards
> Shashank Mani
> BIT Mesra
>
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--
Dinesh Bansal
The Law of Win says, "Let's not do it your way or my way; let's do it the
best way."
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