Hi,
Here is the simple solution
unsigned int r = v; // r will be reversed bits of v; first get LSB of v
int s = sizeof(v) * CHAR_BIT - 1; // extra shift needed at end
for (v >>= 1; v; v >>= 1)
{
r <<= 1;
r |= v & 1;
s--;
}
r <<= s; // shift when v's highest bits are zero
if (v == r)
printf("palindrome\n");
else
printf("not a palindrome\n");
source and more optimized versions
http://www-graphics.stanford.edu/~seander/bithacks.html#BitReverseObvious
-
Azhar.
On Wed, Dec 22, 2010 at 2:09 PM, pacific pacific <[email protected]>wrote:
>
>
> On Wed, Dec 22, 2010 at 12:11 PM, mo...@ismu <[email protected]> wrote:
>
>>
>>
>> if x is a 32 bit number
>> if((x&0x0000FFFF)==((x>>16)&0x0000FFFF)))
>> x's bit pattern is a polyndrome
>>
>> @snehal :Do you want to consider binary representation of 5 as 101 or
> 0000..0101 ?
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