will an o(n^2) do ? , i have one in mind but will that suffice ?

anyways , here it goes
make array
a[array_length][2];
a[k][0] and a[k][1] will contain the no. of 0's and 1 till kth position.
just iterate twice to see where
a[i][0]-a[j][0]==a[i][1]-a[j][1]
can be maximized . meanwhile i am thinking of other solution . . . .


On Tue, Jan 4, 2011 at 2:08 PM, bittu <[email protected]> wrote:

> You have a array of 0's and 1's. e.g.
> 0001011101001010100101010101100111
> Find the maximum contiguous subsequence of the above sequence so the
> number of 0's and 1's in that subsequence are equal
>
>
> Regards
> Shashank Mani
>
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