yes,u can use matrix exponentiation On Sun, Jan 9, 2011 at 3:49 PM, shady <[email protected]> wrote: > hi all, > > Is there a way to find a formula for the nth element of a linear recurrence > ? Instead of going linearly one by one,,,, > c1, c2, c3 are the three constants. > a(n+3) = c1*a(n+2) - c2*a(n+1) + c3*a(n) > > thanks. > > shady > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. >
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