so if its in another subtree, whats the problem? If z is not reachable print 'no'.
On Sun, Jan 9, 2011 at 5:32 PM, juver++ <[email protected]> wrote: > Your approach is failed! Read my previous post. > There is a simple counterexample when doing dfs from x we cannot reach > target node cause z can be placeed into another subtree, so > x is not its ancestor. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- S.Nishaanth, Computer Science and engineering, IIT Madras. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
