1 + 2 + .... + n ( max diagonal) = n ( n + 1) / 2. Max elements you can store is n ( n + 1) / 2 . You can take an array of size n (n + 1) / 2 and store them.
Thanks, Sathaiah On Wed, Jan 12, 2011 at 9:50 AM, Azhar Hussain <[email protected]> wrote: > I have a symmetric matrix. I am wondering what would be the best data > structure to store such a matrix? How many elements do I need to store for a > nxn matrix? > > Thanks in advance for the help. > > - > Azhar. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<algogeeks%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
