thanks

On 25 January 2011 01:50, Balaji Ramani <[email protected]> wrote:

> We do not compare to a value. We compare each pair to current min and if
> the absolute sum of the current pair is less than the current min, we make
> the current pair sum the current min.
>
> Do checkout this link: http://geeksforgeeks.org/?p=4034
>
> Thanks,
> Balaji.
>
> On Tue, Jan 25, 2011 at 9:35 AM, siddharth srivastava <[email protected]
> > wrote:
>
>> Hi
>>
>> On 24 January 2011 12:55, Balaji Ramani <[email protected]>wrote:
>>
>>> @Siddharth
>>>
>>> However if the input range is unknown, it can be solved through an
>>> entirely different approach after sorting and then using two pointers moving
>>> either side from the positive-negative boundary. O(nlogn) + O(n)  = O(nlogn)
>>>
>>
>> yes I meant this case only. But to what value would you compare if you
>> want the sum to be closest to zero and lets say that  none of the elements
>> sum up to zero.
>>
>>>
>>> Thanks,
>>> Balaji.
>>>
>>>
>>> On Mon, Jan 24, 2011 at 11:03 PM, siddharth srivastava <
>>> [email protected]> wrote:
>>>
>>>> If the same question is modified as:
>>>> Find two numbers whose sum is closest to zero in the given array.
>>>>
>>>>
>>>> On 24 January 2011 16:08, juver++ <[email protected]> wrote:
>>>>
>>>>> Its name is meet-in-the-middle technique.
>>>>>
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>>>>
>>>>
>>>> --
>>>> Siddharth Srivastava
>>>>
>>>> When you have learned to snatch the error code from the trap frame, it
>>>> will be time for you to leave.
>>>>
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>>
>>
>> --
>> Siddharth Srivastava
>>
>> When you have learned to snatch the error code from the trap frame, it
>> will be time for you to leave.
>>
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-- 
Siddharth Srivastava

When you have learned to snatch the error code from the trap frame, it will
be time for you to leave.

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