How can we pass pointers by value. Lets say even if it creates a copy of the
pointer.
The address stored by the pointer is the same. So when we dereference it
shouldnt it get updated(as its just a memory address)?

On Thu, Jan 27, 2011 at 5:39 PM, ritu <[email protected]> wrote:

> Here you are passing record pointer by value.
>
> as you call insert(record, 5),stack frame of insert contains a copy
> of  record.after this value is modified by calling program,it should
> be either returned explicitly to caller program or needs to be passed
> by reference,so that calling program refers to it always by address.
>
>
> On Jan 27, 4:17 pm, nishaanth <[email protected]> wrote:
> > Hi guys,
> >
> > I have a small doubt regarding pointers and functions.
> >
> > Consider the following prototype
> >
> > void insert(bst * head, int data);
> >
> > This function creates a node and inserts the data in the node. Lets say i
> > call this function iteratively from main.
> >
> > main(){
> >
> > bst* record=NULL;
> > insert(record, 5);
> > insert(record, 8);
> >
> > }
> >
> > I see that record is not getting modified. Now is this related to call by
> > value. But since we are passing pointers shouldnt the change get
> reflected
> > in main.
> > isnt is similar to passing an array?
> > Enlighten me in this regard. I am tired of segfaults :(
> >
> > Regards,
> > S.Nishaanth,
> > Computer Science and engineering,
> > IIT Madras.
>
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-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

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