@ Sankalp : plz explain this line of yours : No. of As=A*(total number
of keystrokes)  , gives us a bound . We
should have a lower bound as this , we can always get this much As

On Jan 29, 5:32 pm, sankalp srivastava <[email protected]>
wrote:
> We can do it Using a binary search approach (The cost function is
> monotonic over here , so we can use binary search)
>
> No. of As=A*(total number of keystrokes)  , gives us a bound . We
> should have a lower bound as this , we can always get this much As
>
> Take the initial value as high and low as possible
>
> say left=1 and right=10^9
> mid=left+right/2;
> if(can_get(this much As))
>        then , left=mid+1;
>
> else if(cannot get this much As)
>         then ,
>               right=mid
> Continue this search until left<right .. This binary search gives the
> maximum value which you can get using the given combinations

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