@snehal..i guess you are missing something in the question...divide it into
2 groups such that (there should be some other condition or criterion).....

On Sun, Jan 30, 2011 at 11:29 AM, snehal jain <[email protected]> wrote:

> my approach
>
> sort in nlogn and then while traversing the array put the elements in a
> group till they are consecutive . when a[i+1]!=a[i]+1 then put a[i+1] in
> different group.. now we need to rearrange elements in the group so that
> they are according to the given array.. but that will make it O(n^2) ..
> anyone with better ideas?
>
>
> On Fri, Jan 21, 2011 at 1:20 PM, snehal jain <[email protected]>wrote:
>
>> Divide a list of numbers into groups of consecutive numbers but their
>> original order should be preserved.
>> Example:
>> <8,2,4,7,1,0,3,6>
>> Two groups:
>> <2,4,1,0,3> <8,7,6>
>> Better than O(n^2) is expected.
>>
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-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

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