@above

Use Simple Mathematics What is collinear Point...?? what is condition
of collinearity..?? thats it You have done

Three or more points P1, P2, P3, ..., are said to be collinear if they
lie on a single straight line  L  similarly for N Points ..

Let us start from the Very Basic Mathematical  Approach

Since any 2 points determine 1 line, take 2 of the points and find the
equation of the line drawn thru these 2 points.
Substitute the x and y of the either point into the equation and find
the y-intercept (b)

Then, substitute the x and y of the 3rd point into the equation and
see if the both sides of the equation are =.

(y2-y1) ÷ (x2 - x1) = slope

y = slope * x + b


Point # 1 = (6, 5)=p1
Point # 2 = (10, 25)=p1
Point # 3 = (12, 30)=p1
Point # 4 = (12, 35)=p1


(y2 - y1) ÷ (x2 - x1) = slope
(25 - 5) ÷ (10 - 6) = slope
(20) ÷ (4) = slope
Slope = 5
y = m * x + b
y = 5 * x + b

Substitute the x and y of the point (6, 5) into the equation and find
the y-intercept (b)
y = 5 * x + b
5 = 5 * 6 + b
5 = 30 + b
b = -25
y = 5 * x - 25
.
Check your points
Point # 1 = (6, 5)
5 = 5 * 6 - 25
5 = 30 - 25 OK
.
Point # 2 = (10, 25)
25 = 5 * 10 - 25
25 = 5 * 10 - 25 OK
.
Then, substitute the x and y of the 3rd point into the equation and
see if the both sides of the equation are
Point # 3 = (12, 30)
.
y = 5 * x - 25
30 = 5 * 12 - 25
30 = 60 - 25 = 35
Point # 3 = (12, 30) is not on the line
.
.
Point # 4 = (12, 35)
35 = 5 * 12 - 25
35 = 60 - 25 =35
Point # 4 = (12, 35) is on the line

so we can p1,p2,p4 are Collinear


2nd Appraoch Used by Actual Geeks

as we Two points are trivially collinear since two points determine a
line.

Three points x_i=(xi,yi,zi) for i=1, 2, 3 are collinear if the ratios
of distances satisfy

x2-x1:y2-y1:z2-z1=x3-x1:y3-y1:z3-z1

A slightly more notice  that the area  of a triangle  determined by
three points will be zero iff  they are collinear (including the
degenerate cases of two or all three points being concurrent), i.e.,

| x1 y1 1 |
| x2 y2 1 |=0
| x3 y3 1 |


or, in expanded form,
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0

Still If You Have the Doubt Let Me Know & if Any found that anything
wrong in this..please write correct & efficient ways  to do it.

Thanks & Regards
Shashank ""The best way to escape from a problem is to solve it."
.

.

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