i also think the same as 14 and 15 On Mon, Feb 7, 2011 at 6:40 PM, tech rascal <[email protected]> wrote:
> @ anand: I didn't understand > in printf, u r evaluating the values frm right to left n thn while > printing, u hv to print the evaluated values, y u r again evaluating the > values while u r printing frm left to right?? > > as in, u said- > > "Now it try to display the value from left to right which makes a++ as 13, > then a has 14 and ++a as 14" > > so it has to be....acc. to u....a++ as 13, thn a as 14 and thn ++a shd b 15 > thn. > > On Mon, Feb 7, 2011 at 11:01 AM, jagannath prasad das <[email protected] > > wrote: > >> @juver:in f(a)+f(b) i guess f(a) is evaluated first because fucntion calls >> are evaluated from left to right >> >> >> On Mon, Feb 7, 2011 at 10:37 AM, Anand <[email protected]> wrote: >> >>> a++ when it gets printed. it is 13 and now it gets increment to 14. So >>> now if you print a it will 14. >>> >>> >>> On Sun, Feb 6, 2011 at 9:04 PM, jagannath prasad das < >>> [email protected]> wrote: >>> >>>> @anand:while printing post fix gave 13 but rest two why 14 >>>> >>>> On Mon, Feb 7, 2011 at 10:28 AM, Anand <[email protected]> wrote: >>>> >>>>> int a=10,b; >>>>> b=a++ + ++a; (Till here I think it is clear the value of a is 12 and b >>>>> = 22) >>>>> printf("%d,%d,%d,%d",b,a++,a,++a); (Evaluate from right to left. So >>>>> ++a makes the value of a as 13, then a and then a++ which is post >>>>> increment >>>>> still makes a as 13) >>>>> Now it try to display the value from left to right which makes a++ as >>>>> 13, then a has 14 and ++a as 14 >>>>> >>>>> I hope it is clear. >>>>> >>>>> >>>>> On Sun, Feb 6, 2011 at 8:40 PM, jagannath prasad das < >>>>> [email protected]> wrote: >>>>> >>>>>> ya i also want the explaination of gcc compiler output.......thanx in >>>>>> advance >>>>>> >>>>>> On Sun, Feb 6, 2011 at 10:13 AM, tech rascal <[email protected] >>>>>> > wrote: >>>>>> >>>>>>> but can nybody explain why the output is coming like this on gcc >>>>>>> compiler?? >>>>>>> On Sun, Feb 6, 2011 at 10:04 AM, Manish Verma < >>>>>>> [email protected]> wrote: >>>>>>> >>>>>>>> >>>>>>>> i think juver has explained >>>>>>>> On Feb 5, 9:34 pm, jagannath prasad das <[email protected]> >>>>>>>> wrote: >>>>>>>> > @manish:can you explain with the example of a specific compiler... >>>>>>>> > >>>>>>>> > On Sat, Feb 5, 2011 at 10:02 PM, jagannath prasad das >>>>>>>> > <[email protected]>wrote: >>>>>>>> > >>>>>>>> > >>>>>>>> > >>>>>>>> > > @ankit:ans is 22 13 14 14 in gcc compiler............. >>>>>>>> > >>>>>>>> > > On Sat, Feb 5, 2011 at 7:24 PM, Manish Verma < >>>>>>>> [email protected]>wrote: >>>>>>>> > >>>>>>>> > >> answer will depend on your compiler..... >>>>>>>> > >>>>>>>> > >> On Feb 5, 1:02 am, jagannath prasad das <[email protected]> >>>>>>>> wrote: >>>>>>>> > >> > *#include<stdio.h> >>>>>>>> > >> > void main(void) >>>>>>>> > >> > { >>>>>>>> > >> > int a=10,b; >>>>>>>> > >> > b=a++ + ++a; >>>>>>>> > >> > printf("%d,%d,%d,%d",b,a++,a,++a); >>>>>>>> > >>>>>>>> > >> > } >>>>>>>> > >>>>>>>> > >> > *what is the answer?how are the function parameters passed on >>>>>>>> the stack? 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