search for modified josephus problem. you will get the answer :)

On Wed, Feb 9, 2011 at 4:52 PM, punnu <[email protected]> wrote:
> Suppose n people are arranged in a circle. Number the people from 1 to
> n. in the clockwise order. We are given an integer ,m <= n. Beginning
> with the person with designated number 1, we proceed around the circle
> (in clockwise order) removing every mth person. After each person is
> removed, counting continues around the circle that
> remains. This process continues until all the n people have been
> removed. . The .m-permutation is defined as the order in which the
> people have been removed. As an example, if n = 7, m = 3, then the 3 -
> permutation is 3,6,2,7,5,1,4.
> Give an O(n log n) time algorithm which given m and n outputs the m-
> permutation.
>
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