My one cent:

I think one greedy approach solve thus if you only sort the array of string
and then concatenate follow the order


Wladimir Araujo Tavares
*Federal University of CearĂ¡

*




On Thu, Feb 17, 2011 at 12:05 AM, simplyamey <[email protected]>wrote:

> Try this code.
>
> #include<iostream>
> #include<string>
> using namespace std;
> int main()
> {
>        string sArray[5] ={"aab","abc","bba","acc","bcc"};
>
>        int n = 5;
>
>        for(int i = 0;i < n; i++)
>        {
>                for( int j = 0; j < n - 1 ; j++)
>                {
>                        if(sArray[j] > sArray[j+1])
>                        {
>                                string temp = sArray[j];
>                                sArray[j] = sArray[j + 1];
>                                sArray[j+1]= temp;
>                        }
>                }
>        }
>
> string sTemp;
> for(int k = 0; k < n ;k++)
> {
>        sTemp = sTemp + sArray[k];
> }
> cout<<"printing result::"<< sTemp<<endl;
> }
>
> n = Number of strings.
>
> On Feb 17, 9:56 am, bittu <[email protected]> wrote:
> > Given a group of strings, find a string by concatenating all the
> > strings in any order which produces the lexicographically smallest
> > string.
> > For e.g strings are acc bcc abb
> > So the string formed should be abbaccbcc
> >
> > Thanks
> > Shashank
>
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