In a boarding school there are fifteen schoolgirls who always take
their daily walks in rows of threes. How can it be arranged so that
each schoolgirl walks in the same row with every other schoolgirl
exactly once a week? Solution of this problem is equivalent to
constructing a Kirkman triple system of order n=2. The following table
gives one of the 7 distinct (up to permutations of letters) solutions
to the problem. A visualization is shown above.
Sun     ABC     DEF     GHI     JKL     MNO
Mon     ADH     BEK     CIO     FLN     GJM
Tue     AEM     BHN     CGK     DIL     FJO
Wed     AFI     BLO     CHJ     DKM     EGN
Thu     AGL     BDJ     CFM     EHO     IKN
Fri     AJN     BIM     CEL     DOG     FHK
Sat     AKO     BFG     CDN     EIJ     HLM


(The table of Dörrie 1965 contains four omissions in which the a_1=B
and a_2=C entries for Wednesday and Thursday are written simply as
a.)


Thanks & Regrads
Shashank

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