let p be the probability second game success probability is 3*[x^2(1-x)]+x^2
first game success probability is x find for which x ,3*[x^2(1-x)]+x^2<x,this case game1 preffreed and for which x ,3*[x^2(1-x)]+x^2>x,this case game2 preffreed On Mar 2, 4:15 am, bittu <[email protected]> wrote: > You have a basketball hoop and someone says that you can play 1 of 2 > games. > Game #1: You get one shot to make the hoop. > Game #2: You get three shots and you have to make 2 of 3 shots. > If p is the probability of making a particular shot, for which values > of p should you pick one game or the other? > > Thanks & Regards > Shashank -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
