On Sat, Mar 5, 2011 at 5:37 PM, Gopi <[email protected]> wrote: > n = 2^(b-1)
Shouldn't this be n = SUM (2^k) where k = 0 to b-1? > each box should have x dollars where x is of from 2^y, y ranges from 0 > to (b-1). > > On Mar 5, 9:12 am, CodeTrooper <[email protected]> wrote: >> I guess solution would be based on prime numbers. >> >> On Mar 5, 3:11 am, bittu <[email protected]> wrote: >> >> >> >> >> >> >> >> > “You have b boxes and n dollars. If I want any amount of money from 0 >> > to n dollars, you must be able to hand me 0 to b boxes so that I get >> > exactly what I request.” The two questions were “What are the >> > restrictions on b and n, and how is money distributed among the >> > boxes?” >> >> > Thanks >> > Shashank > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
