hey we can do like dis man using trial and error, so start with m = 15, 22,
29 etc. obviuosly we cant start with 8 as n must be greater than 1. I think
u people got the reason for starting with 15(1+14 is divisible by 7),
22(1+21 is divisible by 7) etc.

test for m = 15;

Day 1:- medals = 1+14/7 = 3;
Day 2:- medals = 2 + 10 which is not divisible by 7

test for m = 22;

Day 1:- medals = 1+21/7=4;
Day 2:- medals = 2+16 which is not divisible by 7

test for m = 29;

Day 1:- medals = 1+28/7 = 5;
Day 2:-medals = 2+22 which is not divisible by 7

test for m = 36

Day 1:- medals = 1+35/7=6;
Day 2:- medals = 2+28/7=6;
Day 3:- meadals = 3+21/7 = 6;
Day 4:- medals = 4+ 14/7 = 6;
Day 5:- medals = 5+7/7 = 6;
Day 6:- medals = 6;

So m = 36 and n = 6. Hope I am clear.



On Fri, Mar 18, 2011 at 12:02 PM, bittu <[email protected]> wrote:

> Hi here is the basic approach as we know in a week atmost  7 days ..so
> start with hit and trial
>
> Total 36 medals were awarded and the contest was for 6 days.
>
> On day 1: Medals awarded = (1 + 35/7) = 6 : Remaining 30 medals
> On day 2: Medals awarded = (2 + 28/7) = 6 : Remaining 24 medals
> On day 3: Medals awarded = (3 + 21/7) = 6 : Remaining 18 medals
> On day 4: Medals awarded = (4 + 14/7) = 6 : Remaining 12 medals
> On day 5: Medals awarded = (5 +7/7) = 6 : Remaining 6 medals
> On day 6: Medals awarded 6
>
> Clear and Simple
>
> Thanks
> Sahshank
>
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