@Ganesha it has been several times here i m re-posting again here have
look at it , You can also find it several places by goggling it
basically we have to Print all combination of points that can compose
a given number
Examples:
For n = 1, the program should print following:
1
For n = 2, the program should print following:
1 1
2
For n = 3, the program should print following:
1 1 1
1 2
2 1
3
For n = 4, the program should print following:
1 1 1 1
1 1 2
1 2 1
1 3
2 1 1
2 2
3 1
and so on …
Algorithm:
At first position we can have three numbers 1 or 2 or 3.
First put 1 at first position and recursively call for n-1.
Then put 2 at first position and recursively call for n-2.
Then put 3 at first position and recursively call for n-3.
If n becomes 0 then we have formed a combination that compose n, so
print the current combination
/* The function prints all combinations of numbers 1, 2, ...MAX_POINT
that sum up to n.
i is used in recursion keep track of index in arr[] where next
element is to be added. Initital value of i must be passed as 0 */
void printCompositions(int n, int i)
{
/* array must be static as we want to keep track
of values stored in arr[] using current calls of
printCompositions() in function call stack*/
static int arr[ARR_SIZE];
if (n == 0)
{
printArray(arr, i);
}
else if(n > 0)
{
int k;
for (k = 1; k <= MAX_POINT; k++)
{
arr[i]= k;
printCompositions(n-k, i+1);
}
}
}
Let Me Know if You facing Any problem
Thanks & Regards
Shashank Mani
CSE,BIT Mesra
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