now the case 9 is matching so it gets executed...n da break statement is encountered...
On Wed, Mar 23, 2011 at 8:35 PM, cegprakash <[email protected]> wrote: > > i=9; > switch(i){ > default: printf("default"); > case 9: printf("one"); break; > case '2': printf("two"); break; > case '9': printf("nine"); break; > } > > but how the hell we get output for the above code as "one" .. why > "default" not printed > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
