re.findall(r'a([^a]*)a','000a1111a2222a3333a4444a') On Mar 24, 3:40 pm, DD <[email protected]> wrote: > >>> re.findall(r'a(.*)a','000a1111a2222a3333a4444a') return > > ['1111a2222a3333a4444'] > > what is the regular expression such that it should return > ['1111','2222','3333','4444'] > > ?
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