Plz correct me if i am wrong
On Sun, Mar 27, 2011 at 4:50 PM, saurabh singh <[email protected]> wrote:

> I dont think so even if a solution which appears to be better than o(n) can
> actually be better.Because with this approach we are working upon each input
> test case rather than storing them somewhere and traversing it again.The
> only way this program can be improoved is in terms of memory i feel.
>
>
> On Sun, Mar 27, 2011 at 4:41 PM, sukhmeet singh <[email protected]>wrote:
>
>> is there a better solution than O(n) ??? any datastructure possible
>>
>> On Wed, Mar 23, 2011 at 8:20 PM, .bashrc <[email protected]> wrote:
>>
>>> I may be wrong but if no==1000 then it becomes a[1000000] which is
>>> beyond your array limit....
>>>
>>> On Mar 18, 12:31 am, KK <[email protected]> wrote:
>>> > i m getting TLE for this soln and m not getting the concept used in
>>> > the above soln can anyone help??
>>> > #include<iostream>
>>> > using namespace std;
>>> > int main()
>>> > {
>>> >     int t,n,k,no,flag;
>>> >     scanf("%d",&t);
>>> >     while(t--)
>>> >     {
>>> >               scanf("%d",&n);
>>> >               k = n;
>>> >               int a[1000000] = {0};
>>> >               flag = 0;
>>> >               while(k--)
>>> >               {
>>> >                         scanf("%d",&no);
>>> >                         a[no + 1000]++;
>>> >                         if(a[no + 1000] > n/2)
>>> >                         {
>>> >                              printf("YES %d\n",no);
>>> >                              flag = 1;
>>> >                              break;
>>> >                         }
>>> >               }
>>> >               if(flag == 0)
>>> >                   printf("NO\n");
>>> >     }
>>> >     return 0;
>>> >
>>> > }
>>> >
>>> > On Mar 16, 12:13 am, UTKARSH SRIVASTAV <[email protected]>
>>> > wrote:
>>> >
>>> > > tahnks balaji i have got ac in this problem ........my prog is same
>>> only in
>>> > > the end i have taken a loop and
>>> > > @ akshata the link for the prob ishttps://
>>> www.spoj.pl/problems/MAJOR/
>>> > > MY CODE IS
>>> > > #include<stdio.h>
>>> > > main()
>>> > > {
>>> > >     long long int n,t,r[1000000],count,major,i;
>>> > >     scanf("%lld",&t);
>>> > >     while(t--)
>>> > > {
>>> > >     scanf("%lld",&n);
>>> > >     scanf("%lld",&r[0]);
>>> > >     major=r[0];
>>> > >     count=1;
>>> > >     for(i=1;i<n;i++)
>>> > >     {
>>> > >         scanf("%lld",&r[i]);
>>> > >         if(r[i]!=major)
>>> > >         {
>>> > >             count--;
>>> > >             if(count<0)
>>> > >             {        count=1;
>>> > >                     major=r[i];
>>> > >             }
>>> > >         }
>>> > >         else
>>> > >         {
>>> > >             count++;
>>> > >         }
>>> > >     }
>>> > >     /*if(count<=0)
>>> > >     printf("NO\n");
>>> > >     else
>>> > >     printf("YES%lld\n",major);*/
>>> > >    count=0;
>>> > >     for(i=0;i<n;i++)
>>> > >     {
>>> > >                     if(r[i]==major)
>>> > >                     count++;
>>> > >     }
>>> > >     if(count>n/2)
>>> > >     printf("YES %lld\n",major);
>>> > >     else
>>> > >     printf("NO\n");}
>>> >
>>> > > scanf("%lld",&r[0]);
>>> > > return 0;
>>> >
>>> > > }
>>> >
>>> > > On Tue, Mar 15, 2011 at 10:34 AM, Balaji Ramani
>>> > > <[email protected]>wrote:
>>> >
>>> > > >http://www.spoj.pl/problems/MAJOR/
>>> >
>>> > > > <http://www.spoj.pl/problems/MAJOR/>Thanks,
>>> > > > Balaji.
>>> >
>>> > > > On Tue, Mar 15, 2011 at 11:00 PM, Akshata Sharma <
>>> > > > [email protected]> wrote:
>>> >
>>> > > >> hey link to the problem??
>>> >
>>> > > >> On Tue, Mar 15, 2011 at 10:50 PM, Balaji Ramani <
>>> > > >> [email protected]> wrote:
>>> >
>>> > > >>> It fails for input 1,2,3. I think there needs to be one more
>>> iteration to
>>> > > >>> check if the candidate is actually a majority element or not.
>>> >
>>> > > >>> Thanks,
>>> > > >>> Balaji.
>>> >
>>> > > >>> On Tue, Mar 15, 2011 at 9:50 PM, UTKARSH SRIVASTAV <
>>> > > >>> [email protected]> wrote:
>>> >
>>> > > >>>> CAN ANYONE PLEASE TELL ME WHY MY CODE IS GIVING WRONG ANSWER OR
>>> SOMEONE
>>> > > >>>> WHO HAS GOT AC IN THIS PROBLEM MAY POST HIS SOLUTION
>>> >
>>> > > >>>> #include<stdio.h>
>>> > > >>>> main()
>>> > > >>>> {
>>> > > >>>>     long long int n,t,r,count,major,i;
>>> > > >>>>     scanf("%lld",&t);
>>> > > >>>>     while(t--)
>>> > > >>>> {
>>> > > >>>>     scanf("%lld",&n);
>>> > > >>>>     scanf("%lld",&r);
>>> > > >>>>     major=r;
>>> > > >>>>     count=1;
>>> > > >>>>     for(i=1;i<n;i++)
>>> > > >>>>     {
>>> > > >>>>         scanf("%lld",&r);
>>> > > >>>>         if(r!=major)
>>> > > >>>>         {
>>> > > >>>>             count--;
>>> > > >>>>             if(count<0)
>>> > > >>>>             {        count=1;
>>> > > >>>>                     major=r;
>>> > > >>>>             }
>>> > > >>>>         }
>>> > > >>>>         else
>>> > > >>>>         {
>>> > > >>>>             count++;
>>> > > >>>>         }
>>> > > >>>>     }
>>> > > >>>>     if(count<=0)
>>> > > >>>>     printf("NO\n");
>>> > > >>>>     else
>>> > > >>>>     printf("YES%lld\n",major);
>>> > > >>>> }
>>> > > >>>> return 0;
>>> > > >>>> }
>>> >
>>> > > >>>> --
>>> > > >>>> *UTKARSH SRIVATAV*
>>> > > >>>> *CSE-3
>>> > > >>>> B-Tech 2nd Year
>>> > > >>>> @MNNIT ALLAHABAD*
>>> >
>>> > > >>>>  --
>>> > > >>>> You received this message because you are subscribed to the
>>> Google
>>> > > >>>> Groups "Algorithm Geeks" group.
>>> > > >>>> To post to this group, send email to [email protected]
>>> .
>>> > > >>>> To unsubscribe from this group, send email to
>>> > > >>>> [email protected].
>>> > > >>>> For more options, visit this group at
>>> > > >>>>http://groups.google.com/group/algogeeks?hl=en.
>>> >
>>> > > >>>  --
>>> > > >>> You received this message because you are subscribed to the
>>> Google Groups
>>> > > >>> "Algorithm Geeks" group.
>>> > > >>> To post to this group, send email to [email protected].
>>> > > >>> To unsubscribe from this group, send email to
>>> > > >>> [email protected].
>>> > > >>> For more options, visit this group at
>>> > > >>>http://groups.google.com/group/algogeeks?hl=en.
>>> >
>>> > > >>  --
>>> > > >> You received this message because you are subscribed to the Google
>>> Groups
>>> > > >> "Algorithm Geeks" group.
>>> > > >> To post to this group, send email to [email protected].
>>> > > >> To unsubscribe from this group, send email to
>>> > > >> [email protected].
>>> > > >> For more options, visit this group at
>>> > > >>http://groups.google.com/group/algogeeks?hl=en.
>>> >
>>> > > >  --
>>> > > > You received this message because you are subscribed to the Google
>>> Groups
>>> > > > "Algorithm Geeks" group.
>>> > > > To post to this group, send email to [email protected].
>>> > > > To unsubscribe from this group, send email to
>>> > > > [email protected].
>>> > > > For more options, visit this group at
>>> > > >http://groups.google.com/group/algogeeks?hl=en.
>>> >
>>> > > --
>>> > > *UTKARSH SRIVATAV*
>>> > > *CSE-3
>>> > > B-Tech 2nd Year
>>> > > @MNNIT ALLAHABAD*
>>>
>>> --
>>> You received this message because you are subscribed to the Google Groups
>>> "Algorithm Geeks" group.
>>> To post to this group, send email to [email protected].
>>> To unsubscribe from this group, send email to
>>> [email protected].
>>> For more options, visit this group at
>>> http://groups.google.com/group/algogeeks?hl=en.
>>>
>>>
>>  --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
>> To post to this group, send email to [email protected].
>> To unsubscribe from this group, send email to
>> [email protected].
>> For more options, visit this group at
>> http://groups.google.com/group/algogeeks?hl=en.
>>
>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
>


-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to 
[email protected].
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to