The second cost will be 5+23 irrespective of the end. Correct me u think
otherwise.

On Mon, Mar 28, 2011 at 10:44 PM, Raunak Agrawal <[email protected]>wrote:

> @Kunal:
>
>
> Eg: Rope 1: Size 10 mtr
>       Rope 2: Size 13 mtr
>       Rope 3: Size 5 mtr
>
>
> Cost of tying rope 1 and rope 2 = 10 +13 = 23
>
> Now we have tow end...one for rope 1 and another for rope 2 which can be
> tied with rope 3.
>
> So tie Rope 3 end with rope 2 end : (Length of rope 2 + 3) = (5 + 13) = 18
>
> So total cost = 23 +18 = 41.
>
>
> So for different combination we can have different cost....please let me
> know in case there is any doubt.
>
> On Mon, Mar 28, 2011 at 10:35 PM, Kunal <[email protected]>wrote:
>
>> If you have already tied ropes 1 and 2 then their final length would be 23
>> now you are left with two ropes o length 23 and 5 which suns out to be 28.
>> This remains the same in each of your two examples.
>>
>> Why did you add 13 twice ? I mean you can tie them in 28 cost if you first
>> tie any two and then tie with the left one. Why use 3 knots when it can be
>> done in 2 !!
>>
>> Sent from my iPhone
>>
>> On Mar 28, 2011, at 8:36 PM, Raunak Agrawal <[email protected]>
>> wrote:
>>
>> I think the possible solution is :
>>
>> *Tie the highest two ropes at the end of the rope.*
>> *
>> *
>> This is because of the following reason:
>>
>> Eg: Rope 1: Size 10 mtr
>>       Rope 2: Size 13 mtr
>>       Rope 3: Size 5 mtr
>>
>> Rope1--> Rope2--> Rope3       Cost: (10+13) + (13+5) = 41
>>
>> Rope1-->Rope3--> Rope2      Cost: (10+5) + (5+13) = 33
>>
>>
>> So the optimum cost is : *1st Highest length Rope + 2*(Length of all
>> other ropes other that two having the highest size) + 2nd Highest Rope*.
>>
>>
>> On Mon, Mar 28, 2011 at 7:49 PM, Gunjan Sharma <<[email protected]>
>> [email protected]> wrote:
>>
>>> The question seems to be correct. Think again....
>>>
>>>
>>> On Mon, Mar 28, 2011 at 5:24 PM, kunal srivastav 
>>> <<[email protected]>
>>> [email protected]> wrote:
>>>
>>>> if you tie all of them and the cost is sum of invidual lengths then in
>>>> the end the cost will be sum of all lengths irrespective of any order that
>>>> we tie them in..
>>>> i think the ques would req you to say that the cost is the longer of the
>>>> two..plz check
>>>>
>>>>
>>>> On Mon, Mar 28, 2011 at 12:11 PM, bittu < <[email protected]>
>>>> [email protected]> wrote:
>>>>
>>>>> you are given n ropes,maybe of different length. the cost of tying two
>>>>> ropes is the sum of their lengths.Find a way to tie these ropes
>>>>> together so that the cost is minimum.
>>>>>
>>>>>
>>>>>
>>>>> Thanks
>>>>> Shashank
>>>>>
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>>> Regards
>>> Gunjan Sharma
>>> Chairman IEEE Students Chapter IIT Roorkee
>>> B.Tech IV year CSE
>>>
>>> Contact No- +91 9997767077
>>>
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Regards
Gunjan Sharma
Chairman IEEE Students Chapter IIT Roorkee
B.Tech IV year CSE

Contact No- +91 9997767077

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