then please share wid me yaar
thanks in advance

On Mon, Apr 4, 2011 at 4:30 PM, Manmeet Singh <[email protected]> wrote:

> Simple Dp
>
>
> On Mon, Apr 4, 2011 at 3:33 PM, Munish Goyal <[email protected]>wrote:
>
>> I think we can do it this way.
>>
>> Sum(all boards length) / K = A ( tentative avg. lenght to be painted by
>> each painter)
>>
>> Now start from B1, and keep going further till Bi, till Sum(B1-Bi) is less
>> than A. So this goes to painter P1.
>>
>> Same way for P2, start from i+1 till j.
>>
>> Condition: If  i+1 itself is > A. Then new A = length(B i+1).
>>
>> Keep going like this till Bn
>>
>>
>> On Mon, Apr 4, 2011 at 3:20 PM, rajat ahuja 
>> <[email protected]>wrote:
>>
>>> like u hav boards of length of length
>>> 7 2 6 9 4 and u hav 3 painters who can work ||ly
>>> so now
>>> one way to distribute is
>>> (7 )(2 6 9) (4) so time in ths case is 17
>>> suppose we do (7 2)(6)(9 4) time  in ths case is 13
>>> or i can do (7 2)(6 9 )(4) time in ths case is 15
>>>  i m takin 1 unit time to paint one meter so it is directly equal to
>>> length
>>>
>>>
>>> so we hav to make time and ans is 13
>>>
>>> On Mon, Apr 4, 2011 at 3:11 PM, Rakib Ansary Saikot <
>>> [email protected]> wrote:
>>>
>>>> I didnt quite get this problem. Sample case?
>>>>
>>>> On 4/4/11, rajat ahuja <[email protected]> wrote:
>>>> > You have to paint N boards of length {B1, B2, B3… BN}. There are K
>>>> painters
>>>> > available and you are also given how much time a painter takes to
>>>> paint 1
>>>> > unit of board. You have to get this job done as soon as possible under
>>>> the
>>>> > constraints that any painter will only paint continuous sections of
>>>> board,
>>>> > say board {2, 3, 4} or only board {1} or nothing but not board {2, 4,
>>>> 5}.
>>>> >
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>>>> >
>>>>
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>>
>>
>> --
>> Munish
>>
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