lets say there are two pointers - temp1,temp2 and the start of the node is
head....
now,
  temp1=head;
  temp2=head->next;

 temp1->next=temp2->next;

 now temp1 points to the first node and the temp2 points to the second
node(which got deleted from the list).....

On Thu, Apr 7, 2011 at 5:43 PM, Umer Farooq <the.um...@gmail.com> wrote:

> That can be moved. Basically, he is trying to convey that move the data of
> temp->next to temp. That's perfectly fine.
>
>
> On Thu, Apr 7, 2011 at 2:05 PM, Akash Mukherjee <akash...@gmail.com>wrote:
>
>> @ anurag
>>
>> temp -> data = ( temp -> next ) -> data ;
>>
>> but data cannot be moved, ryt??
>>
>> On 4/6/11, Anurag atri <anu.anurag....@gmail.com> wrote:
>> > in case you are given a pointer to the first node simply do
>> > temp ->next = ( temp -> next ) -> next .
>> > if you are given a pointer to the second node do ,
>> > temp -> data = ( temp -> next ) -> data ;
>> > temp -> next = NULL ;
>> >
>> > correct me if I am wrong .
>> >
>> > On Mon, Apr 4, 2011 at 9:48 PM, Umer Farooq <the.um...@gmail.com>
>> wrote:
>> >
>> >> Hello friends,
>> >>
>> >> The following question has appeared in two top companies of my city.
>> I'd
>> >> appreciate if anyone is able to answer it.
>> >>
>> >> Given a singly liked list comprising of three nodes
>> >>
>> >> Delete the middle node such that:
>> >>
>> >> 1- A temp pointer is pointing to the first node
>> >> 2- A temp pointer is pointing to the second node.
>> >>
>> >> You can not use any other pointer and you can not move data.
>> >>
>> >> --
>> >> Umer
>> >>
>> >> --
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>> >>
>> >
>> >
>> >
>> > --
>> > Regards
>> > Anurag Atri
>> >
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>
>
> --
> Umer
>
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-- 
A.Balaji

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