As i mention earlier this s a literal...
Wel a literal as is allotted space in the memory.. Think its heaps..
Then a reference is made to tat location in the declaration of char pointer..
You can access it but cant be altered...:-)
Regards,
Keybo
-----Original message-----
From: riti gupta
Sent: 21/04/2011, 4:25 pm
To: [email protected]
Subject: Re: [algogeeks]
Than y r we able to do the following
main()
{
char *p="hello";
p="bye";
}
On Thu, Apr 21, 2011 at 4:21 PM, Sudhir mishra <[email protected]>wrote:
> yes there is error;
> first allocate memory for p;
>
>
> On Thu, Apr 21, 2011 at 6:44 AM, riti gupta <[email protected]> wrote:
>
>> is there any error in following code?
>>
>> main
>> {
>> char *p="hello";
>> p[0]='j';
>> p[1]='j';
>> puts(p);
>> }
>>
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>
>
>
> --
>
> [image: motilal.JPG]
> Thanks & Regards...*
> SUDHIR MISHRA <[email protected]>*
> *IT 3rd YEAR*
> *Motilal Nehru National institute Of Technology-ALLAHABAD.
> *
>
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