1000-floor(1000) gives 0
therefore n is divisible by 5

________________________________
From: ADITYA KUMAR <[email protected]>
To: [email protected]
Sent: Thursday, 5 May 2011 7:30 AM
Subject: Re: [algogeeks] Divisibility by five


anshu sols is best
@venkat what if b=1000


On Thu, May 5, 2011 at 7:12 AM, venkatesan B <[email protected]> 
wrote:

b=n*0.2;
>if((b-floor(b))==0)
>print " number is divisible by 5";
>else
>print " number is not divisible by 5";
>
>
>________________________________
> From: Umer Farooq <[email protected]>
>To: [email protected]
>Sent: Tuesday, 3 May 2011 10:27 AM
>Subject: Re: [algogeeks] Divisibility by five
>
>
>public static isDivisibleByFive(int input)
>{String str_input = String.valueof(input); // convert initial int to string.
>if ((str_input.charat(str_input.length()-1) == '5') || 
>(str_input.charat(str_input.length()-1) == '0') // check if the last character 
>is 0 or 5
>.... return true;
>return false;
>}
>
>
>u can try something like this ... 
>
>On Tue, May 3, 2011 at 9:25 AM, Dave <[email protected]> wrote:
>
>Given an integer n, give an O(log n) algorithm to determine if n is
>>divisible by 5 without using division or mod.
>> 
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>
>
>-- 
>Umer
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-- 
Regards
Aditya Kumar
B-tech 3rd year
Computer Science & Engg.
MNNIT, Allahabad.

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