hey...bt this one works only in case given that the elements of the array
are non-negative.

On Fri, May 27, 2011 at 2:30 PM, bhavana <[email protected]> wrote:

> @sukhi : instead of using a map...use a boolean array elements of whoch r
> initialised to false.
>
> Starting frm the first element of the array....if the number n is greater
> than k ignore it....else mark a[n]=true and check if a[k-n]==true then we
> get the required result .....bt if we reach the end of array without
> entering the if condition the array doesnt contain any such pair.
>
>
> On Fri, May 27, 2011 at 2:26 PM, sukhmeet singh <[email protected]>wrote:
>
>> @bhavana : Explain..!!
>> as far as i get you is that  it would  be same as implementing map ...!!
>> isn't ??
>>
>>
>> On Fri, May 27, 2011 at 2:16 PM, bhavana <[email protected]> wrote:
>>
>>> can be solved easily if the elements of the array lie in a limited range
>>> which can b known beforehand...!!
>>>
>>>
>>> On Fri, May 27, 2011 at 2:10 PM, Aakash Johari <[email protected]>wrote:
>>>
>>>> yes, you are right. map insertion takes O(log n) time. so if you know
>>>> the upper bound of N, you can simply map the existence/non-existence of any
>>>> particular element in an array. that will be in constant time (for query
>>>> purposes) and O(n) time for preprocessing.
>>>>
>>>>
>>>> On Fri, May 27, 2011 at 1:29 AM, sukhmeet singh <[email protected]
>>>> > wrote:
>>>>
>>>>> @Dave nd @Akash can u explain a bit more.. I didn't get what u say..
>>>>> Inserting in a map takes O(log n)  time !!
>>>>>
>>>>> On Fri, May 20, 2011 at 8:35 PM, Aakash Johari 
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> @Dave: This is what is still a doubt to me. I have searched but
>>>>>> couldn't get the info regarding this.
>>>>>>
>>>>>>
>>>>>> On Fri, May 20, 2011 at 8:01 AM, Dave <[email protected]>wrote:
>>>>>>
>>>>>>> @Aakash: And tell me how map works. Is making an entry O(1)
>>>>>>> regardless
>>>>>>> of the value of the entry? For example, is it O(n) to map the
>>>>>>> sequence
>>>>>>> 1, 4, 9, 16, 25, ..., n^2?
>>>>>>>
>>>>>>> Dave
>>>>>>>
>>>>>>> On May 20, 9:39 am, Aakash Johari <[email protected]> wrote:
>>>>>>> > @Dave: I got you. I will have to check before pushing the element
>>>>>>> in map.
>>>>>>> >
>>>>>>> >
>>>>>>> >
>>>>>>> >
>>>>>>> >
>>>>>>> > On Fri, May 20, 2011 at 7:30 AM, Dave <[email protected]>
>>>>>>> wrote:
>>>>>>> > > @Aakash: Yeah, but try the same array with sum = 6 and see what
>>>>>>> > > happens.
>>>>>>> >
>>>>>>> > > Dave
>>>>>>> >
>>>>>>> > > On May 20, 9:04 am, Aakash Johari <[email protected]> wrote:
>>>>>>> > > > int main()
>>>>>>> > > > {
>>>>>>> > > >         int a[10] = {5, 3, 10, 9, 8, 23, 11, 4, 12, 6};
>>>>>>> > > >         int i;
>>>>>>> > > >         int sum;
>>>>>>> > > >         int flag = 0;
>>>>>>> >
>>>>>>> > > >         map<int, int> m;
>>>>>>> >
>>>>>>> > > >         for ( i = 0; i < 10; i++ ) {
>>>>>>> > > >                 m[a[i]] = 1;
>>>>>>> > > >         }
>>>>>>> >
>>>>>>> > > >         sum = 13;
>>>>>>> >
>>>>>>> > > >         for ( i = 0; i < 10; i++ ) {
>>>>>>> > > >                 if ( m[sum - a[i]] == 1 ) {
>>>>>>> > > >                         flag = 1;
>>>>>>> > > >                         break;
>>>>>>> > > >                 }
>>>>>>> > > >         }
>>>>>>> >
>>>>>>> > > >         if ( flag == 1 )
>>>>>>> > > >                 cout << a[i] << " " << sum - a[i] << endl;
>>>>>>> >
>>>>>>> > > >         return 0;
>>>>>>> >
>>>>>>> > > > }
>>>>>>> > > > On Fri, May 20, 2011 at 7:01 AM, hari <[email protected]>
>>>>>>> wrote:
>>>>>>> > > > > We can sort using STL sort function in main() before function
>>>>>>> call of
>>>>>>> > > > > arraysum().
>>>>>>> >
>>>>>>> > > > > On May 20, 6:49 am, Gunjan Sharma <[email protected]>
>>>>>>> wrote:
>>>>>>> > > > > > First of all there is an infinite loop in this code....
>>>>>>> > > > > > Secondly it works only for sorted array.
>>>>>>> >
>>>>>>> > > > > > On Fri, May 20, 2011 at 7:16 PM, hari <
>>>>>>> [email protected]> wrote:
>>>>>>> > > > > > > In while loop have i,j which points first and last index
>>>>>>> of array.
>>>>>>> > > In
>>>>>>> > > > > > > while loop, Check the sum of a[i],a[j], If
>>>>>>> sum<k,increment i or
>>>>>>> > > else
>>>>>>> > > > > > > decrement j. Run the while loop till i<j..
>>>>>>> >
>>>>>>> > > > > > > CODE:
>>>>>>> >
>>>>>>> > > > > > > int arraysum(int a[], int k, int i, int j)
>>>>>>> > > > > > > while(i<j)
>>>>>>> > > > > > > {
>>>>>>> > > > > > >  int p=0;
>>>>>>> > > > > > >  int b[10];     //to store index of selected nos
>>>>>>> > > > > > >  sum=a[i]+a[j];
>>>>>>> > > > > > >  if (sum==k)
>>>>>>> > > > > > >  {
>>>>>>> > > > > > >  b[p++]=i;b[p++]=j;
>>>>>>> > > > > > >  }
>>>>>>> > > > > > >  elseif(sum<k)
>>>>>>> > > > > > >  i++;
>>>>>>> > > > > > >  else(sum>k)
>>>>>>> > > > > > >  j++;
>>>>>>> > > > > > >  return b;
>>>>>>> > > > > > > }
>>>>>>> >
>>>>>>> > > > > > > On May 20, 4:38 am, amit <[email protected]>
>>>>>>> wrote:
>>>>>>> > > > > > > > given an array of integers, and an integer k, find out
>>>>>>> two
>>>>>>> > > elements
>>>>>>> > > > > > > > from the array whose sum is k in O(n) time. if no such
>>>>>>> element
>>>>>>> > > exists
>>>>>>> > > > > > > > output none.
>>>>>>> >
>>>>>>> > > > > > > --
>>>>>>> > > > > > > You received this message because you are subscribed to
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>>>>>>> > > > > Groups
>>>>>>> > > > > > > "Algorithm Geeks" group.
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>>>>>>> > > > > > > To unsubscribe from this group, send email to
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>>>>>>> >
>>>>>>> > > > > > --
>>>>>>> > > > > > Regards
>>>>>>> > > > > > Gunjan Sharma
>>>>>>> > > > > > B.Tech IV year CSE
>>>>>>> >
>>>>>>> > > > > > Contact No- +91 9997767077
>>>>>>> >
>>>>>>> > > > > --
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>>>>>>> >
>>>>>>> > > > --
>>>>>>> > > > -Aakash Johari
>>>>>>> > > > (IIIT Allahabad)- Hide quoted text -
>>>>>>> >
>>>>>>> > > > - Show quoted text -
>>>>>>> >
>>>>>>> > > --
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>>>>>>> >
>>>>>>> > --
>>>>>>> > -Aakash Johari
>>>>>>> > (IIIT Allahabad)- Hide quoted text -
>>>>>>> >
>>>>>>> > - Show quoted text -
>>>>>>>
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>>>>>>>
>>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> -Aakash Johari
>>>>>> (IIIT Allahabad)
>>>>>>
>>>>>>
>>>>>>
>>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> -Aakash Johari
>>>> (IIIT Allahabad)
>>>>
>>>>
>>>>
>>>>
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