you may want to check how the floats and doubles are stored into
memory using ieee notation.
i tried to print 0.08 and 0.08f in hex format and got the following result.
vishal@ubuntu:~/progs/c\ 10:03:56 AM >$ cat fl.c
#include <stdio.h>
int main()
{
float f=0.08;
if (f < 0.08f)
printf("hi\n");
else
printf("hello\n");
printf ("%x %x\n",0.08, 0.08f);
return 0;
}
vishal@ubuntu:~/progs/c\ 10:04:06 AM >$ gcc fl.c
fl.c: In function ‘main’:
fl.c:10: warning: format ‘%x’ expects type ‘unsigned int’, but
argument 2 has type ‘double’
fl.c:10: warning: format ‘%x’ expects type ‘unsigned int’, but
argument 3 has type ‘double’
vishal@ubuntu:~/progs/c\ 10:04:11 AM >$ ./a.out
hello
47ae147b 3fb47ae1
vishal@ubuntu:~/progs/c\ 10:04:14 AM >$
ps: please ignore the warning in the code.
On Sun, May 29, 2011 at 10:23 PM, sravanreddy001
<[email protected]> wrote:
> and, I read it long time back that.. the value of 0.8 alone will be stored
> as 0.799999999995 (not sure on the number of 9's but.. the last digit in the
> precision will be a 5)
> that could be a reason.
> may be what "vishal" said is correct.
>
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