ya i have seen many questions like this in this group.......its all because of sequence points the output varies from compiler to compiler
On Jun 4, 9:10 pm, nicks <[email protected]> wrote: > i agree this type of expressions are not defined and are depend on the > machine...... > it's something like a[i]=i++; > the result may vary from machine to machine ! > > On Sat, Jun 4, 2011 at 5:00 PM, Rohit Sindhu <[email protected] > > > > > > > > > wrote: > > > 1. If the operand values is to be stored in temporaries the first > > evaluation will make one operand to be 4 and next evaluation make > > the other one to be 5. So in this case the result is 4*5 = 20. > > > 2. But if variable b is to be used as operands the result will be 5*5 = 25 > > > As a good practice using sub -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
