@Amit Jaspal...there is a fundamental error in the code related to
pointers....u have incremented the pointers p and x..so before the printf
loop, pointer p (as well as x) is pointing to 4th location...I hope I am
clear...
this can be done by creating two more pointers that will initialised as the
base location of p and x...
#include <stdio.h>
int main(){
int *p,*a,i=0;
void *x,*b;
p=(int *)malloc(3*sizeof(int));
* a =p;*
x=malloc(24);
* b = x;*
p[0]=1;
p[1]=2;
p[2]=3;
p[3]=4;
while(i<4){
*((int *)x)=*p;
((int *)x)++;
p++;
i++;
}
for(i=0;i<4;i++){
*printf("%d\n",a[i]);
printf("%d\n",((int *)b)[i]);*
}
system("pause");
return 0;
}
On Sun, May 29, 2011 at 11:38 PM, amit <[email protected]> wrote:
> Suppose I want to copy an integer array to another array pointed by a
> void pointer of different size.
> Some thing like this is done probably in realloc function.
>
> The problem is it is not working for me ... here's the code
>
> #include <stdio.h>
> int main(){
>
> int *p,i=0;
> void *x;
> p=(int *)malloc(3*sizeof(int));
> x=malloc(24);
> p[0]=1;
> p[1]=2;
> p[2]=3;
> p[3]=4;
> while(i<4){
> *((int *)x)=*p;
> ((int *)x)++;
> p++;
> i++;
> }
>
> for(i=0;i<4;i++){
> printf("%d\n",p[i]);
> printf("%d\n",((int *)x)[i]);
> }
> return 0;
> }
>
>
> Can anyone suggest what is happening wrong in this code.....or what
> can be a better way to do this.
>
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