Ma approach is to xor the given number with all numbers in the file !!
This takes O(n)
I think we cant achieve a complexity <O(n)
we have to scan the file at least once

Or move to this problem
Instead of a file with numbers
you have a stream of numbers

Create a Trie and insert every number from the stream by reversing the
digits of the number
Now u have a Trie (left as 0 bit && right as 1 bit )

u are going to check whether a number N exist
reverse the bits of N
search for appropriate bit in the Trie
if all bit are matched then there is a number !!
else No

But Space Complexity Of Trie is high  we need (32 *(O(n)) assuming each
integer is of 32 bits




On Thu, Jun 9, 2011 at 4:54 PM, Dumanshu <[email protected]> wrote:

> Given a file containing roughly 300 million social security numbers(9-
> digit numbers) find a 9-digit number that isnt there in the file. You
> have unlimited drive space but only 2mb of RAM.
>
> Solution is as follows:
> In the first step, we build an array of 2^16 integers that is
> initialized to 0 and for every number in the file we take its 16 most
> significant
> bit to index into this array and increment that number. Since there
> are less than 2^32 numbers in the file there is bound to be one number
> in the array that is less than 2^16 . This tells us that there is at
> least one number missing among the possible numbers with those upper
> bits. In the second pass, we can focus only on the numbers that match
> this criterion and use a bit-vector of size 2^16 to identify one of
> the missing numbers.
>
> Someone plz explain this solution( may be using some small values
> numbers) or suggest another approach.
>
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