but program by anika is giving *7 6 8* on gcc.....but *7 6 6 *on
dev-cpp...........i am wondering if the output is compiler dependent !!

On Sun, Jun 12, 2011 at 6:33 AM, nicks <[email protected]> wrote:

> no it's
> a=1 b=1
> i=2
>
> i ran it on gcc (linux ubuntu 11.04)
>
>
> On Sun, Jun 12, 2011 at 6:26 AM, sanjay ahuja 
> <[email protected]>wrote:
>
>> with GCC the above code gives a = 1 and b = 2
>>
>>
>> On Sun, Jun 12, 2011 at 6:39 PM, nicks <[email protected]>
>> wrote:
>> > @himanshu....what abt this ??
>> >
>> > #include<stdio.H>
>> > # include <conio.h>
>> > int i=2;
>> > main()
>> > {
>> >  void add();
>> >  add(i++,--i);
>> >     printf("\ni=%d \n",i);system("pause");
>> > }
>> > void add(int a ,int b)
>> > {
>> >  printf("\na=%d b=%d",a,b);
>> > }
>> >
>> >  OUTPUT -
>> > a=1 b=1
>> > i=2
>> >
>> > acc. to ur logic output should be -
>> > a=1 b=2
>> > i=2
>> >
>> >
>> > On Sun, Jun 12, 2011 at 5:42 AM, Anika Jain <[email protected]>
>> wrote:
>> >>
>> >> thanks himanshu finally i got the reason!!
>> >> :)
>> >>
>> >> On Sun, Jun 12, 2011 at 5:59 PM, himanshu kansal
>> >> <[email protected]> wrote:
>> >>>
>> >>> @anika:cz on gcc arguemnts r eval frm right to left and assgnment to a
>> >>> pre increment expression is delayed vry mch....
>> >>> so on eval frm right to left....
>> >>> frst a is incremented...(6) bt remember d new value is nt pushed on
>> stack
>> >>> till nw....(cz assgnmnt is delayed)
>> >>> thn next value is 6...nd thn a is incremented.....here being a post
>> >>> increment op....assgnmnt is made 1st (2nd arg to fun is 6)and a is
>> >>> incrementd to 7....
>> >>> simalrly.....assgnmnt is made(1st arg is 7) and a is incremnted to
>> 8.....
>> >>> nw d assgnmnt is made to the 3rd arg(d assgnmnt whch ws delayed till
>> >>> nw).....hence 3rd arg becomes 8.....
>> >>> so it prints 7 6 8......
>> >>>
>> >>> On Sun, Jun 12, 2011 at 5:33 PM, Anika Jain <[email protected]>
>> >>> wrote:
>> >>>>
>> >>>> can anybody explain that in following code y output is coming to be:
>> 7 6
>> >>>> 8
>> >>>>
>> >>>> void call(int a,int b,int c)
>> >>>> {
>> >>>>          printf("%d %d %d",a,b,c);
>> >>>> }
>> >>>>
>> >>>> int main()
>> >>>> {
>> >>>> int a=5;
>> >>>> call(a++,a++,++a);
>> >>>> return 0;
>> >>>> }
>> >>>>
>> >>>>
>> >>>> On Sat, Jun 11, 2011 at 8:21 PM, PRAMENDRA RATHi rathi
>> >>>> <[email protected]> wrote:
>> >>>>>
>> >>>>> IN second program:
>> >>>>>  in function value are always push in the stack from right.
>> >>>>> so first value is --i that will make i=1 and value 1 will be passed
>> to
>> >>>>> function
>> >>>>> and
>> >>>>> after that i++ that's means i will be passed.
>> >>>>> so 1 will be passed and after passing value. i will changed to 2.
>> >>>>>
>> >>>>> if u want to know why reverse order than can go through:
>> >>>>>
>> >>>>> http://cs.nyu.edu/courses/fall03/V22.0201-003/c_param.html
>> >>>>> -----------------------------------------
>> >>>>> PRAMENDRA RATHI
>> >>>>> NIT ALLAHABAD
>> >>>>>
>> >>>>>
>> >>>>>
>> >>>>>
>> >>>>> On Sat, Jun 11, 2011 at 7:28 PM, Vishal Thanki <
>> [email protected]>
>> >>>>> wrote:
>> >>>>>>
>> >>>>>> In 1st program, 2nd printf requires one more argument. And
>> basically
>> >>>>>> %a is used for printing a double value in hex. see "man 3 printf".
>> >>>>>>
>> >>>>>> On Sat, Jun 11, 2011 at 5:29 PM, nicks <[email protected]
>> >
>> >>>>>> wrote:
>> >>>>>> > Hello friends..plz help me in understanding the following C
>> Output
>> >>>>>> >
>> >>>>>> > first one is --
>> >>>>>> >
>> >>>>>> > #include<stdio.h>
>> >>>>>> > #include<conio.h>
>> >>>>>> > main()
>> >>>>>> > {
>> >>>>>> > int a=5;
>> >>>>>> > printf("a=%d\n",a);
>> >>>>>> > printf("%a=%d",a);
>> >>>>>> > getch();
>> >>>>>> > }
>> >>>>>> > OUTPUT -
>> >>>>>> > a=5
>> >>>>>> > 0x1.2ff380p-1021=4199082
>> >>>>>> >
>> >>>>>> >
>> >>>>>> > and the other one is --
>> >>>>>> >
>> >>>>>> > #include<stdio.H>
>> >>>>>> > # include <conio.h>
>> >>>>>> > int i=2;
>> >>>>>> > main()
>> >>>>>> > {
>> >>>>>> >  void add();
>> >>>>>> >  add(i++,--i);
>> >>>>>> >     printf("\ni=%d \n",i);system("pause");
>> >>>>>> > }
>> >>>>>> > void add(int a ,int b)
>> >>>>>> > {
>> >>>>>> >  printf("\na=%d b=%d",a,b);
>> >>>>>> > }
>> >>>>>> >
>> >>>>>> >  OUTPUT -
>> >>>>>> > a=1 b=1
>> >>>>>> > i=2
>> >>>>>> >
>> >>>>>> > --
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>> >>>
>> >>>
>> >>> --
>> >>>
>> >>>       Regards
>> >>> Himanshu Kansal
>> >>>   Msc Comp. sc.
>> >>> (University of Delhi)
>> >>>
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>>
>> --
>> Sanjay Ahuja,
>> Analyst, Financing Prime Brokerage
>> Nomura Securities India Pvt. Ltd
>>
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