Oops, there's a bug in my analysis! the sort complexity is even better at
O(N) :)
If you're doing K merges of subarrays of size O( N / K ) (which is the
worst case for this algo due to the merge cost of O(min{N, M}) ) using the
reverse operation you've supplied, the result is an O(N) sort instead of an
O(N log N) sort. Win! :)
--
DK
http://twitter.com/divyekapoor
http://www.divye.in
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