"hi friends" is a string literal.. ie the string "hi friends" is stored
somewhere and a pointer to its base address is returned to pointer p at the
time of initialization... u can always make use of this pointer to traverse
/ access the "literal" but u cant "alter tat" in the code, u r trying to do
a "++" operation, which throws a seg fault....

On Thu, Jun 16, 2011 at 2:16 PM, Kamakshii Aggarwal
<[email protected]>wrote:

> i still din't get the solution..please explain..
>
> On 6/16/11, LALIT SHARMA <[email protected]> wrote:
> > ++*p++
> > ==>
> > ++(*p++) ,
> > increments the value stored at p , and also increments p .
> >
> >
> >
> > On Thu, Jun 16, 2011 at 1:10 PM, sunny agrawal
> > <[email protected]>wrote:
> >
> >> The place where strict constness is not enforced is with character
> >> array literals. You can say
> >> char* cp = "howdy";
> >> and the compiler will accept it without complaint. This is
> >> technically an error because a character array literal (“howdy” in
> >> this case) is created by the compiler as a constant character array,
> >> and the result of the quoted character array is its starting address in
> >> memory. Modifying any of the characters in the array is a runtime
> >> error, although not all compilers enforce this correctly.
> >> So character array literals are actually constant character arrays. Of
> >> course, the compiler lets you get away with treating them as nonconst
> >> because there’s so much existing C code that relies on this.
> >> However, if you try to change the values in a character array literal,
> >> the behavior is undefined, although it will probably work on many
> >> machines.
> >> If you want to be able to modify the string, put it in an array:
> >> char cp[] = "howdy";
> >> Since compilers often don’t enforce the difference you won’t be
> >> reminded to use this latter form and so the point becomes rather
> >> subtle.
> >>
> >>
> >> On Thu, Jun 16, 2011 at 12:59 PM, amit kumar
> >> <[email protected]>wrote:
> >>
> >>> //kk
> >>> //In place of
> >>>
> >>> char *p="hai friends",*p1;
> >>> if i declare as
> >>> char p[]="hai friends";
> >>> char *p1;
> >>> //then ??
> >>>
> >>>
> >>> On Thu, Jun 16, 2011 at 8:16 AM, DIPANKAR DUTTA <
> >>> [email protected]> wrote:
> >>>
> >>>> It's ok..
> >>>>
> >>>> char *p="hai friends"...not correct....
> >>>>
> >>>> bcz you did allocate memory for that string but assiging poiter to the
> >>>> base address.. from where gcc will get the bse address of that string
> >>>> when u
> >>>> r not actually allocate memory for it? thus it generate SIGSEG signal
> >>>> and
> >>>> give invalid memory address...ie. segmentation fault
> >>>> use malloc or use
> >>>> char p[]="..";
> >>>>
> >>>>
> >>>>
> >>>>
> >>>>
> >>>>
> >>>> On Thu, Jun 16, 2011 at 4:49 AM, DK <[email protected]> wrote:
> >>>>
> >>>>> Gives me a SEGFAULT on gcc.
> >>>>> Probably due to undefined behaviour.
> >>>>>
> >>>>> --
> >>>>> DK
> >>>>>
> >>>>> http://twitter.com/divyekapoor
> >>>>> http://www.divye.in
> >>>>>
> >>>>> --
> >>>>> You received this message because you are subscribed to the Google
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> >>>>> https://groups.google.com/d/msg/algogeeks/-/QVAjKMQiWvoJ.
> >>>>>
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> >>>>>
> >>>>
> >>>>
> >>>>
> >>>> --
> >>>> Thanks and Regards,
> >>>> ------------------------------
> >>>> *DIPANKAR DUTTA*
> >>>> Visiting Research Scholar
> >>>> Dept of Computing,
> >>>> Macquarie University, Sydney, Australia
> >>>> ph.no-+61 2 98509079 ( Mon-Fri 10:15-7:00) Sydney time
> >>>> email: [email protected]
> >>>>
> >>>>
> >>>>
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> >>>
> >>
> >>
> >>
> >> --
> >> Sunny Aggrawal
> >> B-Tech IV year,CSI
> >> Indian Institute Of Technology,Roorkee
> >>
> >>
> >>  --
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> >>
> >
> >
> >
> > --
> > Lalit Kishore Sharma,
> >
> > IIIT Allahabad (Amethi Capmus),
> > 6th Sem.
> >
> > --
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> >
>
>
> --
> Regards,
> Kamakshi
> [email protected]
>
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>

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