@sharma: dis has been explained to tiwari...ask him...:)

On Fri, Jun 17, 2011 at 3:12 AM, DIPANKAR DUTTA
<[email protected]>wrote:

> instead of calling swap(&ps[0],&ps[1]) can u try with swap(ps[0],ps[1]) or
> swap(&ps[0][0],&ps[1][0]) ?
>
> On Fri, Jun 17, 2011 at 5:05 AM, udit sharma <[email protected]>wrote:
>
>> #include<stdio.h>void swap(char *,char *);int main(){char *ps[2]={
>>              "Hello",
>>              "Good Mornning",
>>      };swap(&ps[0],&ps[1]);printf("%s \t %s\n",ps[0],ps[1]);return 0;}
>> void swap(char *p,char *q){char *t;t=p;p=q;q=t;}
>>
>>
>> why the output is:
>> Hello         Good Mornning
>>
>>
>>
>>
>>
>>
>>
>> --
>> Regards
>>  UDIT
>>  DU- MCA
>>
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>
>
>
> --
> Thanks and Regards,
> ------------------------------
> *DIPANKAR DUTTA*
> Visiting Research Scholar
> Dept of Computing,
> Macquarie University, Sydney, Australia
> ph.no-+61 2 98509079 ( Mon-Fri 10:15-7:00) Sydney time
> email: [email protected]
>
>
>
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-- 
regards

Apoorve Mohan

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