say the arrays are

a 6,7,9
b 3,4,5
c 1,2,8


the merged array would be

1c
2c
3a
4b
5b
6a
7a
8c
9a

1c,2c cant be compared as they are from same array..next is 3a this implies
3-2 =1 is min distance

P.S: you can merge these in O(m+n+p) [merge from bottom as they are already
sorted]


Best Regards
Ashish Goel
"Think positive and find fuel in failure"
+919985813081
+919966006652


On Sat, Jun 18, 2011 at 12:24 AM, Dumanshu <[email protected]> wrote:

> @Ashish: could u plz explain ur algo in detail. "walk over the merged
> list to get adjacent min distance and different tags" this would be of
> the order O(m*n) say we merge A1 A2 of size m and n respectively.
> Also, now how do u go ahead with the 3rd array? didn't get ur
> solution.
>
> Harshal's solution looks fine. ny bugs?
>
> On Jun 17, 9:13 pm, Ashish Goel <[email protected]> wrote:
> > merge two and if required third  array keeping array tag with the
> elements
> > walk over the merged list and see adjacent distance which is minimum with
> > the condition that the tage of the adjacent elements are different
> >
> > Best Regards
> > Ashish Goel
> > "Think positive and find fuel in failure"
> > +919985813081
> > +919966006652
> >
> >
> >
> > On Fri, Jun 17, 2011 at 9:36 PM, Dumanshu <[email protected]> wrote:
> > > U have got 3 sorted arrays A1 A2 and A3 having m n and p elements
> > > respectively. A gap of 3 arrays is defined to be max distance between
> > > 3 nos if they are put on a no line say u pick three 2 12 and 7 then
> > > the gap is 10. Now u have to find an efficient way of chosing 3 nos
> > > from these 3 seperate arrays (A1, A2, A3) such that their gap is
> > > minimum. Of course if a num say 2 occurs in all 3 then gap is 0!!!
> >
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