Gene is correct :)
Counter example
{1, 2, 2, 5, 5}
See method 3 here http://geeksforgeeks.org/?p=11516


On 6/25/11, Gene <[email protected]> wrote:
> Nice idea, but unfortunately doesn't work. The XOR only contains
> parity information. So just pick two values in the range and a low
> order bit where they're different.  Then swap the bits.
>
> 2 xor 3 xor 4 xor 5 = 0
>
> Pick 3 and 4 and swap the lsb, which gives 2 and 5.  So we have
>
> 2 xor 2 xor 5 xor 5 = 0
>
>
> On Jun 24, 4:12 pm, Piyush Sinha <[email protected]> wrote:
>> I have a solution that will do the job in O(n) time but will require three
>> variables....but this solution won't work if the array contains -ve
>> numbers.
>> *
>> int findrepeat(int a[],int n)
>> {
>>      int i,xor = 0;
>>      int min = findmin(a,n);
>>      int max = findmax(a,n);
>>      if((max-min+1)!=n)
>>          return 0;
>>      for(i = 0 ;i<n;i++)
>>           xor^=a[i];
>>      for(i=min;i<=max;i++)
>>          xor^=i;
>>      if(xor)
>>              return 0;
>>      else
>>           return 1;
>>
>> }*
>>
>> Please let me know if there is any counter example..
>>
>>
>>
>>
>>
>> On Sat, Jun 25, 2011 at 1:17 AM, ross <[email protected]> wrote:
>> > One solution would be to : check if max-min = N and
>> > that all elements are unique in the array.
>> > However, this may require space complexity.. Looking for a
>> > better solution.
>>
>> > On Jun 25, 12:44 am, ross <[email protected]> wrote:
>> > > Given an array, A, find if all elements in the sorted version of A are
>> > > consecutive in less than O(nlogn).
>> > > eg: A: 5 4 1 2 3 on sorting 1 2 3 4 5 all elements are consecutive --
>> > > true
>> > > A: 1 9 2 22 on sorting 1 2 9 22 all elements are NOT consecutive -
>> > > false
>>
>> > --
>> > You received this message because you are subscribed to the Google
>> > Groups
>> > "Algorithm Geeks" group.
>> > To post to this group, send email to [email protected].
>> > To unsubscribe from this group, send email to
>> > [email protected].
>> > For more options, visit this group at
>> >http://groups.google.com/group/algogeeks?hl=en.
>>
>> --
>> *Piyush Sinha*
>> *IIIT, Allahabad*
>> *+91-8792136657*
>> *+91-7483122727*
>> *https://www.facebook.com/profile.php?id=100000655377926*
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to [email protected].
> To unsubscribe from this group, send email to
> [email protected].
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>
>

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to 
[email protected].
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to