Thanks all :).
On 6/25/11, Anantha Krishnan <[email protected]> wrote: > When we declare *char *str="hello";* > > this "hello" will be stored in the read-only memory i.e *TEXT Segment*. > > so when we try to write the read-only memory by **str='w';* it will > throw *Segmentation > fault*. > > Obviously we must allocate some memory in heap to modify it like: > *char *str=(char *)malloc(1024);* > > Thanks & Regards, > Anantha Krishnan > > On Sat, Jun 25, 2011 at 2:16 PM, Adarsh <[email protected]> wrote: > >> char array[] = "hello"; >> char *pointer = "hello"; >> >> array is an array, enough to store sequence of characters and '\0' >> array will always refer to same storage. >> Here, pointer is initialized to point to a string constant, pointer >> may be modified, but you cannot chage string contents >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
