@ Dave How to think about the answer to the above question . I mean How do I
tackle such problems ?

On Mon, Jun 27, 2011 at 6:17 PM, Dave <[email protected]> wrote:

> y = ((x & 0x55) << 1) | ((x >> 1) & 0x55).
>
> Note, 0x55 = 01010101 in binary.
>
> Dave
>
> On Jun 27, 7:18 am, rShetty <[email protected]> wrote:
> > Given a byte, write a code to swap every two bits. [Using bit
> > operators]
> >
> >  Eg: Input: 10 01 11 01 Output: 01 10 11 10
>
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