http://anandtechblog.blogspot.com/2011/06/google-question-find-missing-number.html

On Mon, Jun 27, 2011 at 4:12 PM, aditya kumar
<[email protected]>wrote:

>
> @Kamakshi.thnks.i dint realise that.
>
> On Mon, Jun 27, 2011 at 11:04 PM, sunny agrawal 
> <[email protected]>wrote:
>
>> @saket  - No
>>
>> O(n) + O(n/2) + O(n/4)................... = O(n)
>>
>> sum of series
>> n+n/2+n/4+n/8............ = 2n
>>
>>
>> On Mon, Jun 27, 2011 at 9:26 PM, Sanket <[email protected]> wrote:
>>
>>> @Dave - Wouldn't your solution also become O(kn) where k = number of
>>> bits in the number?
>>> In this summation - O(n) + O(n/2) + O(n/4) + ...= O(n) - you would
>>> have O(n) appearing 'k' times. Each entry is O(n/ 2^i) where 'i' is
>>> the bit position from right to left, starting at 0. The range of 'i'
>>> is from 0 to 'k-1'
>>> Please correct me if I am wrong.
>>>
>>> On Jun 27, 7:29 am, Bhavesh agrawal <[email protected]> wrote:
>>> > can anyone plz post the code for this problem
>>>
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>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
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