Hi Rajeev,

Is there any documentation/link which shows this behavior?

On Wed, Jun 29, 2011 at 8:17 AM, varun pahwa <[email protected]> wrote:
> Here is the attached image of code run in codeblocks. I think its compiler
> dependent that structure can be print like this
> printf("%f %d",2[*arr]); provided format specifiers in order of structure
> elements.
>
>
> On Tue, Jun 28, 2011 at 6:35 PM, [email protected]
> <[email protected]> wrote:
>>
>> its tryin to acess arr[3] which is not defined and null....hence it is
>> giving null and priniting default value 0.0000000.arr[2[ is only the last
>> defined array of structure.
>>
>> On Tue, Jun 28, 2011 at 12:07 PM, udit sharma <[email protected]>
>> wrote:
>>>
>>> I think this is also a compiler dependent program..
>>> Bcz if u run d code
>>>
>>> #include<stdio.h>
>>> typedef struct
>>> {
>>>       char *name;
>>>        double salary;
>>> }job;
>>>
>>> main()
>>> {
>>>     static job a={"tcs",15000.0};
>>>     static job a={"ibm",25000.0};
>>>     static job a={"google",35000.0};
>>>     int x=5;
>>>     job *arr[3]={&a,&b,&c};
>>>      printf("%s %f\t",(3)[*arr]);
>>> }
>>>
>>>
>>> it'll give u : (null) 0.000000
>>> This indicates tat d compiler is evaluating (3)[*arr] in  (3,x>>1)[*arr]
>>>
>>> And if d compiler gives: google 35000.000000 as a result, means it is
>>> evaluating (3,x>>1)[*arr] as (2)[*arr]..
>>> Correct me if m wrong.. :)
>>>
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>
>
>
> --
> Varun Pahwa
> B.Tech (IT)
> 7th Sem.
> Indian Institute of Information Technology Allahabad.
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-- 
Cheers
Naveen Kumar

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