This should be very simple... follow inorder..
Inorder(Node* node, int counter, int N)
{
if(node == null)return;
Inorder(node->left, counter, N);
counter++;
if(counter == N)
{
print(node->data);
return;
}
Inorder(node->right, counter, N);
}
On Wed, Jun 29, 2011 at 9:03 PM, piyush kapoor <[email protected]> wrote:
> Order Statistics Tree
>
>
> On Wed, Jun 29, 2011 at 8:15 PM, sunny agrawal <[email protected]>wrote:
>
>> At each node if we store the Number of nodes in the left subtree.....we
>> can find kth smallest in O(lgn)
>> else do a inorder traversal for k nodes
>>
>> On Wed, Jun 29, 2011 at 8:07 PM, Nishant Mittal <
>> [email protected]> wrote:
>>
>>> how to find kth smallest element in BST...
>>>
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>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
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>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
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