scanf returns no of integers it read,not the read integer.

On 6/26/11, [email protected] <[email protected]> wrote:
> It breaks out correctly when test condition value is 0 i.e when value of t
> is 1....
>
> On Sat, Jun 25, 2011 at 4:41 PM, sunny agrawal
> <[email protected]>wrote:
>
>> No, Read about the return type of scanf
>>
>>
>> On Sun, Jun 26, 2011 at 4:56 AM, amit the cool
>> <[email protected]>wrote:
>>
>>> main()
>>> {
>>> int i,t;
>>> for ( t=4;scanf("%d",&i)-t;printf("%d\n",i))
>>>        printf("%d--",t--);
>>> }
>>>
>>> inputs and corresponding outputs are:
>>> 0
>>> 4--0
>>> 1
>>> 3--1
>>> 2
>>> 2--2
>>> 3
>>> but the loop should break when 2 is given as input.
>>>
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>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
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